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Editor: TadashiIijima
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← Revision 4 as of 2018-10-28 15:21:48 → ⇥
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Editor: TadashiIijima
Comment:
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  • 解答は基本的に，下記 7 行です． 

   1 def judge_high_and_low( x, correct_number ):
   2     if x == correct_number:
   3         return( "正解です" )
   4     elif x > correct_number:
   5         return( "大きすぎます" )
   6     else:
   7         return( "小さすぎます" )
  • でも，単純に，正解なら整数の0, 大きすぎるとき正の数，小さすぎるとき負の数を返すと考えれば，単純に引き算で表現できます． 

   1 def judge_high_and_low( x, correct_number ):
   2     return( int( x - correct_number ))

SoftEng: Python/Prog/Practice/Extended/02/EP_005a/Digest (last edited 2019-10-16 14:42:15 by TadashiIijima)